1/40x^2+1/20x-2=0

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Solution for 1/40x^2+1/20x-2=0 equation: 


x in (-oo:+oo)

(1/40)*x^2+(1/20)*x-2 = 0

1/40*x^2+1/20*x-2 = 0

DELTA = (1/20)^2-(-2*1/40*4)

DELTA = 81/400

DELTA > 0

x = ((81/400)^(1/2)-1/20)/(1/40*2) or x = (-(81/400)^(1/2)-1/20)/(1/40*2)

x = 8 or x = -10

x in { -10, 8 }

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